What are the solutions to the equation -x^2+5x+10=0 ?

The solutions to the equation -x^2+5x+10=0 are x=-(-5+sqrt(65))/2 ,x=(5+sqrt(65))/2

Find the zeros of -x^2+5x+10=0

The zeros of -x^2+5x+10=0 are x=-(-5+sqrt(65))/2 ,x=(5+sqrt(65))/2

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- x^{2} + 5 x + 10 = 0

x = - \frac{- 5 + 65}{2}, x = \frac{5 + 65}{2}

Solution steps

- x^{2} + 5 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 10 = 65

x_{1, 2} = \frac{- 5 \pm 65}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 65}{2 ( - 1 )}, x_{2} = \frac{- 5 - 65}{2 ( - 1 )}

x = \frac{- 5 + 65}{2 ( - 1 )} : - \frac{- 5 + 65}{2}

x = \frac{- 5 - 65}{2 ( - 1 )} : \frac{5 + 65}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 65}{2}, x = \frac{5 + 65}{2}

x^{2} + 9 x + 90 = 0

- \frac{2}{3} x^{2} = 0

2 a^{2} + 17 a + 30 = 0

14 = x^{2} + 10 x

5 t^{2} + 7 t - 200 = 0

What are the solutions to the equation -x^2+5x+10=0 ?
The solutions to the equation -x^2+5x+10=0 are x=-(-5+sqrt(65))/2 ,x=(5+sqrt(65))/2
Find the zeros of -x^2+5x+10=0
The zeros of -x^2+5x+10=0 are x=-(-5+sqrt(65))/2 ,x=(5+sqrt(65))/2