What are the solutions to the equation 5t^2+7t-200=0 ?

The solutions to the equation 5t^2+7t-200=0 are t=(-7+sqrt(4049))/(10),t=(-7-sqrt(4049))/(10)

Find the zeros of 5t^2+7t-200=0

The zeros of 5t^2+7t-200=0 are t=(-7+sqrt(4049))/(10),t=(-7-sqrt(4049))/(10)

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5 t^{2} + 7 t - 200 = 0

t = \frac{- 7 + 4049}{10}, t = \frac{- 7 - 4049}{10}

Solution steps

5 t^{2} + 7 t - 200 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 200 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 200) = 4049

t_{1, 2} = \frac{- 7 \pm 4049}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 7 + 4049}{2 \cdot 5}, t_{2} = \frac{- 7 - 4049}{2 \cdot 5}

t = \frac{- 7 + 4049}{2 \cdot 5} : \frac{- 7 + 4049}{10}

t = \frac{- 7 - 4049}{2 \cdot 5} : \frac{- 7 - 4049}{10}

The solutions to the quadratic equation are:

t = \frac{- 7 + 4049}{10}, t = \frac{- 7 - 4049}{10}

w^{2} - 64 = 0

5 x^{2} + 30 x - 9 = 0

10 - 10 t = 5 t - 2 t^{2}

z, f = z^{2} - 5 z + 22 f (- 2)

- 3 x^{2} + 30 x - 72 = 0

What are the solutions to the equation 5t^2+7t-200=0 ?
The solutions to the equation 5t^2+7t-200=0 are t=(-7+sqrt(4049))/(10),t=(-7-sqrt(4049))/(10)
Find the zeros of 5t^2+7t-200=0
The zeros of 5t^2+7t-200=0 are t=(-7+sqrt(4049))/(10),t=(-7-sqrt(4049))/(10)