What are the solutions to the equation 10-10t=5t-2t^2 ?

The solutions to the equation 10-10t=5t-2t^2 are t=(15-sqrt(145))/4 ,t=(15+sqrt(145))/4

Find the zeros of 10-10t=5t-2t^2

The zeros of 10-10t=5t-2t^2 are t=(15-sqrt(145))/4 ,t=(15+sqrt(145))/4

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10 - 10 t = 5 t - 2 t^{2}

t = \frac{15 - 145}{4}, t = \frac{15 + 145}{4}

Solution steps

10 - 10 t = 5 t - 2 t^{2}

Switch sides

5 t - 2 t^{2} = 10 - 10 t

Move

10 t

to the left side

- 2 t^{2} + 15 t = 10

Move

10

to the left side

- 2 t^{2} + 15 t - 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 2 ) ( - 10 )}{2 ( - 2 )}

1 5^{2} - 4 (- 2) (- 10) = 145

t_{1, 2} = \frac{- 15 \pm 145}{2 ( - 2 )}

Separate the solutions

t_{1} = \frac{- 15 + 145}{2 ( - 2 )}, t_{2} = \frac{- 15 - 145}{2 ( - 2 )}

t = \frac{- 15 + 145}{2 ( - 2 )} : \frac{15 - 145}{4}

t = \frac{- 15 - 145}{2 ( - 2 )} : \frac{15 + 145}{4}

The solutions to the quadratic equation are:

t = \frac{15 - 145}{4}, t = \frac{15 + 145}{4}

z, f = z^{2} - 5 z + 22 f (- 2)

- 3 x^{2} + 30 x - 72 = 0

(x - 3) 2 + 4 = - x^{2}

(x - 2) (3 x + 5) = x (x - 2)

3 x^{2} - 183 = 9

What are the solutions to the equation 10-10t=5t-2t^2 ?
The solutions to the equation 10-10t=5t-2t^2 are t=(15-sqrt(145))/4 ,t=(15+sqrt(145))/4
Find the zeros of 10-10t=5t-2t^2
The zeros of 10-10t=5t-2t^2 are t=(15-sqrt(145))/4 ,t=(15+sqrt(145))/4