What are the solutions to the equation -3x^2+30x-72=0 ?

The solutions to the equation -3x^2+30x-72=0 are x=4,x=6

Find the zeros of -3x^2+30x-72=0

The zeros of -3x^2+30x-72=0 are x=4,x=6

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- 3 x^{2} + 30 x - 72 = 0

x = 4, x = 6

Solution steps

- 3 x^{2} + 30 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 3 ) ( - 72 )}{2 ( - 3 )}

3 0^{2} - 4 (- 3) (- 72) = 6

x_{1, 2} = \frac{- 30 \pm 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 30 + 6}{2 ( - 3 )}, x_{2} = \frac{- 30 - 6}{2 ( - 3 )}

x = \frac{- 30 + 6}{2 ( - 3 )} : 4

x = \frac{- 30 - 6}{2 ( - 3 )} : 6

The solutions to the quadratic equation are:

x = 4, x = 6

(x - 3) 2 + 4 = - x^{2}

(x - 2) (3 x + 5) = x (x - 2)

3 x^{2} - 183 = 9

(y + 6) (y - 2) = - 7

- 2 x - 48 = - x^{2}

What are the solutions to the equation -3x^2+30x-72=0 ?
The solutions to the equation -3x^2+30x-72=0 are x=4,x=6
Find the zeros of -3x^2+30x-72=0
The zeros of -3x^2+30x-72=0 are x=4,x=6