What are the solutions to the equation (y+6)(y-2)=-7 ?

The solutions to the equation (y+6)(y-2)=-7 are y=1,y=-5

Find the zeros of (y+6)(y-2)=-7

The zeros of (y+6)(y-2)=-7 are y=1,y=-5

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(y + 6) (y - 2) = - 7

y = 1, y = - 5

Solution steps

(y + 6) (y - 2) = - 7

Expand

(y + 6) (y - 2) : y^{2} + 4 y - 12

y^{2} + 4 y - 12 = - 7

Move

7

to the left side

y^{2} + 4 y - 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

y_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 6}{2 \cdot 1}, y_{2} = \frac{- 4 - 6}{2 \cdot 1}

y = \frac{- 4 + 6}{2 \cdot 1} : 1

y = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

y = 1, y = - 5

- 2 x - 48 = - x^{2}

3 x^{2} + 10 = - 6 x

x^{2} + 2 + x^{2} + 8 x = 3 x^{2} + 4 x - 10

x, x^{2} + x y = y^{2}

3 x^{2} - 24 x - 100 = 0

What are the solutions to the equation (y+6)(y-2)=-7 ?
The solutions to the equation (y+6)(y-2)=-7 are y=1,y=-5
Find the zeros of (y+6)(y-2)=-7
The zeros of (y+6)(y-2)=-7 are y=1,y=-5