What are the solutions to the equation x^2+2+x^2+8x=3x^2+4x-10 ?

The solutions to the equation x^2+2+x^2+8x=3x^2+4x-10 are x=-2,x=6

Find the zeros of x^2+2+x^2+8x=3x^2+4x-10

The zeros of x^2+2+x^2+8x=3x^2+4x-10 are x=-2,x=6

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x^{2} + 2 + x^{2} + 8 x = 3 x^{2} + 4 x - 10

x = - 2, x = 6

Solution steps

x^{2} + 2 + x^{2} + 8 x = 3 x^{2} + 4 x - 10

Refine

2 x^{2} + 8 x + 2 = 3 x^{2} + 4 x - 10

Move

10

to the left side

2 x^{2} + 8 x + 12 = 3 x^{2} + 4 x

Move

4 x

to the left side

2 x^{2} + 4 x + 12 = 3 x^{2}

Move

3 x^{2}

to the left side

- x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 12}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 12 = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 ( - 1 )}, x_{2} = \frac{- 4 - 8}{2 ( - 1 )}

x = \frac{- 4 + 8}{2 ( - 1 )} : - 2

x = \frac{- 4 - 8}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = - 2, x = 6

x, x^{2} + x y = y^{2}

3 x^{2} - 24 x - 100 = 0

39 = x^{2} - 2 x + 4

x, (x + y_{i})^{2} = 3 - 4 i

x, 4 x^{2} + 9 x + 3 = 0

What are the solutions to the equation x^2+2+x^2+8x=3x^2+4x-10 ?
The solutions to the equation x^2+2+x^2+8x=3x^2+4x-10 are x=-2,x=6
Find the zeros of x^2+2+x^2+8x=3x^2+4x-10
The zeros of x^2+2+x^2+8x=3x^2+4x-10 are x=-2,x=6