What are the solutions to the equation 39=x^2-2x+4 ?

The solutions to the equation 39=x^2-2x+4 are x=7,x=-5

Find the zeros of 39=x^2-2x+4

The zeros of 39=x^2-2x+4 are x=7,x=-5

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39 = x^{2} - 2 x + 4

x = 7, x = - 5

Solution steps

39 = x^{2} - 2 x + 4

Switch sides

x^{2} - 2 x + 4 = 39

Move

39

to the left side

x^{2} - 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 1}

x = \frac{- ( - 2 ) + 12}{2 \cdot 1} : 7

x = \frac{- ( - 2 ) - 12}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

x, (x + y_{i})^{2} = 3 - 4 i

x, 4 x^{2} + 9 x + 3 = 0

2 x^{2} - 3 x + \frac{5}{8} = 0

5 x^{2} - 3 x + 1 = - 3 x^{2} - 2 x

a^{2} + 24 a + 144 = 0

What are the solutions to the equation 39=x^2-2x+4 ?
The solutions to the equation 39=x^2-2x+4 are x=7,x=-5
Find the zeros of 39=x^2-2x+4
The zeros of 39=x^2-2x+4 are x=7,x=-5