What are the solutions to the equation 2x^2-3x+5/8 =0 ?

The solutions to the equation 2x^2-3x+5/8 =0 are x= 5/4 ,x= 1/4

Find the zeros of 2x^2-3x+5/8 =0

The zeros of 2x^2-3x+5/8 =0 are x= 5/4 ,x= 1/4

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2 x^{2} - 3 x + \frac{5}{8} = 0

x = \frac{5}{4}, x = \frac{1}{4}

Solution steps

2 x^{2} - 3 x + \frac{5}{8} = 0

Multiply both sides by

8

16 x^{2} - 24 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 5}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 5 = 16

x_{1, 2} = \frac{- ( - 24 ) \pm 16}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 16}{2 \cdot 16}, x_{2} = \frac{- ( - 24 ) - 16}{2 \cdot 16}

x = \frac{- ( - 24 ) + 16}{2 \cdot 16} : \frac{5}{4}

x = \frac{- ( - 24 ) - 16}{2 \cdot 16} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = \frac{1}{4}

5 x^{2} - 3 x + 1 = - 3 x^{2} - 2 x

a^{2} + 24 a + 144 = 0

5 x^{2} - 50 x + 30 = 0

(x - 10)^{2} = 11

x^{2} + 6 x - (6 + 7) = 0

What are the solutions to the equation 2x^2-3x+5/8 =0 ?
The solutions to the equation 2x^2-3x+5/8 =0 are x= 5/4 ,x= 1/4
Find the zeros of 2x^2-3x+5/8 =0
The zeros of 2x^2-3x+5/8 =0 are x= 5/4 ,x= 1/4