What are the solutions to the equation 97=215x-16x^2 ?

The solutions to the equation 97=215x-16x^2 are x=(215-sqrt(40017))/(32),x=(215+sqrt(40017))/(32)

Find the zeros of 97=215x-16x^2

The zeros of 97=215x-16x^2 are x=(215-sqrt(40017))/(32),x=(215+sqrt(40017))/(32)

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97 = 215 x - 16 x^{2}

x = \frac{215 - 40017}{32}, x = \frac{215 + 40017}{32}

Solution steps

97 = 215 x - 16 x^{2}

Switch sides

215 x - 16 x^{2} = 97

Move

97

to the left side

215 x - 16 x^{2} - 97 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 215 x - 97 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 215 \pm 21 5 ^{2} - 4 ( - 16 ) ( - 97 )}{2 ( - 16 )}

21 5^{2} - 4 (- 16) (- 97) = 40017

x_{1, 2} = \frac{- 215 \pm 40017}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 215 + 40017}{2 ( - 16 )}, x_{2} = \frac{- 215 - 40017}{2 ( - 16 )}

x = \frac{- 215 + 40017}{2 ( - 16 )} : \frac{215 - 40017}{32}

x = \frac{- 215 - 40017}{2 ( - 16 )} : \frac{215 + 40017}{32}

The solutions to the quadratic equation are:

x = \frac{215 - 40017}{32}, x = \frac{215 + 40017}{32}

- 16 x^{2} + 112 x + 128 = 0

n = t^{2} - 12

x^{2} - 2 = 7 x - x^{2}

x^{2} + 12 x - 72 = 0

3 x^{2} + (k - 6) x + 24 = 0

What are the solutions to the equation 97=215x-16x^2 ?
The solutions to the equation 97=215x-16x^2 are x=(215-sqrt(40017))/(32),x=(215+sqrt(40017))/(32)
Find the zeros of 97=215x-16x^2
The zeros of 97=215x-16x^2 are x=(215-sqrt(40017))/(32),x=(215+sqrt(40017))/(32)