What are the solutions to the equation n=t^2-12 ?

The solutions to the equation n=t^2-12 are t=sqrt(n+12),t=-sqrt(n+12)

Find the zeros of n=t^2-12

The zeros of n=t^2-12 are t=sqrt(n+12),t=-sqrt(n+12)

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n = t^{2} - 12

t = n + 12, t = - n + 12

Solution steps

n = t^{2} - 12

Switch sides

t^{2} - 12 = n

Move

12

to the right side

t^{2} = n + 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = n + 12, t = - n + 12

x^{2} - 2 = 7 x - x^{2}

x^{2} + 12 x - 72 = 0

3 x^{2} + (k - 6) x + 24 = 0

1 5^{2} + 1 5^{2} = c^{2}

- 2 m^{2} - 6 m + 5 = 0

What are the solutions to the equation n=t^2-12 ?
The solutions to the equation n=t^2-12 are t=sqrt(n+12),t=-sqrt(n+12)
Find the zeros of n=t^2-12
The zeros of n=t^2-12 are t=sqrt(n+12),t=-sqrt(n+12)