What are the solutions to the equation -2m^2-6m+5=0 ?

The solutions to the equation -2m^2-6m+5=0 are m=-(3+sqrt(19))/2 ,m=(sqrt(19)-3)/2

Find the zeros of -2m^2-6m+5=0

The zeros of -2m^2-6m+5=0 are m=-(3+sqrt(19))/2 ,m=(sqrt(19)-3)/2

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- 2 m^{2} - 6 m + 5 = 0

m = - \frac{3 + 19}{2}, m = \frac{19 - 3}{2}

Solution steps

- 2 m^{2} - 6 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) \cdot 5 = 219

m_{1, 2} = \frac{- ( - 6 ) \pm 2 19}{2 ( - 2 )}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 2 19}{2 ( - 2 )}, m_{2} = \frac{- ( - 6 ) - 2 19}{2 ( - 2 )}

m = \frac{- ( - 6 ) + 2 19}{2 ( - 2 )} : - \frac{3 + 19}{2}

m = \frac{- ( - 6 ) - 2 19}{2 ( - 2 )} : \frac{19 - 3}{2}

The solutions to the quadratic equation are:

m = - \frac{3 + 19}{2}, m = \frac{19 - 3}{2}

2 m^{2} + 17 m - 9 = 0

(3 x - 2) (x + 7) = 0

x^{2} + 3 x = 18

a^{2} - 6 a - 7 = 0

x, 5 x^{2} - 20 x = 0

What are the solutions to the equation -2m^2-6m+5=0 ?
The solutions to the equation -2m^2-6m+5=0 are m=-(3+sqrt(19))/2 ,m=(sqrt(19)-3)/2
Find the zeros of -2m^2-6m+5=0
The zeros of -2m^2-6m+5=0 are m=-(3+sqrt(19))/2 ,m=(sqrt(19)-3)/2