What are the solutions to the equation (3x-2)(x+7)=0 ?

The solutions to the equation (3x-2)(x+7)=0 are x= 2/3 ,x=-7

Find the zeros of (3x-2)(x+7)=0

The zeros of (3x-2)(x+7)=0 are x= 2/3 ,x=-7

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(3 x - 2) (x + 7) = 0

x = \frac{2}{3}, x = - 7

Solution steps

(3 x - 2) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or x + 7 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 7

x^{2} + 3 x = 18

a^{2} - 6 a - 7 = 0

x, 5 x^{2} - 20 x = 0

x, y x^{2} = 3 x^{2} - 8 x + 4

9 = r^{2}

What are the solutions to the equation (3x-2)(x+7)=0 ?
The solutions to the equation (3x-2)(x+7)=0 are x= 2/3 ,x=-7
Find the zeros of (3x-2)(x+7)=0
The zeros of (3x-2)(x+7)=0 are x= 2/3 ,x=-7