What are the solutions to the equation a^2-6a-7=0 ?

The solutions to the equation a^2-6a-7=0 are a=7,a=-1

Find the zeros of a^2-6a-7=0

The zeros of a^2-6a-7=0 are a=7,a=-1

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a^{2} - 6 a - 7 = 0

a = 7, a = - 1

Solution steps

a^{2} - 6 a - 7 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

a_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, a_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

a = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

a = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

a = 7, a = - 1

x, 5 x^{2} - 20 x = 0

x, y x^{2} = 3 x^{2} - 8 x + 4

9 = r^{2}

5 t^{2} - 32 t + 3 = 24

(0.6 x - 3) (2 x + 1) = 0

What are the solutions to the equation a^2-6a-7=0 ?
The solutions to the equation a^2-6a-7=0 are a=7,a=-1
Find the zeros of a^2-6a-7=0
The zeros of a^2-6a-7=0 are a=7,a=-1