What are the solutions to the equation 5t^2-32t+3=24 ?

The solutions to the equation 5t^2-32t+3=24 are t=7,t=-3/5

Find the zeros of 5t^2-32t+3=24

The zeros of 5t^2-32t+3=24 are t=7,t=-3/5

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5 t^{2} - 32 t + 3 = 24

t = 7, t = - \frac{3}{5}

Solution steps

5 t^{2} - 32 t + 3 = 24

Move

24

to the left side

5 t^{2} - 32 t - 21 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 5 ( - 21 )}{2 \cdot 5}

(- 32)^{2} - 4 \cdot 5 (- 21) = 38

t_{1, 2} = \frac{- ( - 32 ) \pm 38}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- ( - 32 ) + 38}{2 \cdot 5}, t_{2} = \frac{- ( - 32 ) - 38}{2 \cdot 5}

t = \frac{- ( - 32 ) + 38}{2 \cdot 5} : 7

t = \frac{- ( - 32 ) - 38}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

t = 7, t = - \frac{3}{5}

(0.6 x - 3) (2 x + 1) = 0

2500 + 700 y + 49 y^{2} + y = 100

w^{2} - 4 w + 3 = 0

[f (a)]^{2} = 4 x^{2} - x + 3

c^{2} - c - 14 = 2 c

What are the solutions to the equation 5t^2-32t+3=24 ?
The solutions to the equation 5t^2-32t+3=24 are t=7,t=-3/5
Find the zeros of 5t^2-32t+3=24
The zeros of 5t^2-32t+3=24 are t=7,t=-3/5