What are the solutions to the equation c^2-c-14=2c ?

The solutions to the equation c^2-c-14=2c are c=(3+sqrt(65))/2 ,c=(3-sqrt(65))/2

Find the zeros of c^2-c-14=2c

The zeros of c^2-c-14=2c are c=(3+sqrt(65))/2 ,c=(3-sqrt(65))/2

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c^{2} - c - 14 = 2 c

c = \frac{3 + 65}{2}, c = \frac{3 - 65}{2}

Solution steps

c^{2} - c - 14 = 2 c

Move

2 c

to the left side

c^{2} - 3 c - 14 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 14) = 65

c_{1, 2} = \frac{- ( - 3 ) \pm 65}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 3 ) + 65}{2 \cdot 1}, c_{2} = \frac{- ( - 3 ) - 65}{2 \cdot 1}

c = \frac{- ( - 3 ) + 65}{2 \cdot 1} : \frac{3 + 65}{2}

c = \frac{- ( - 3 ) - 65}{2 \cdot 1} : \frac{3 - 65}{2}

The solutions to the quadratic equation are:

c = \frac{3 + 65}{2}, c = \frac{3 - 65}{2}

m^{2} - m + 6 = 0

5 c^{2} - 36 c = 32

0 = 40 + 5 t - 4.9 t^{2}

4 x \cdot (2 x + 4) = - 8

2 x^{2} - 7 x = 12

What are the solutions to the equation c^2-c-14=2c ?
The solutions to the equation c^2-c-14=2c are c=(3+sqrt(65))/2 ,c=(3-sqrt(65))/2
Find the zeros of c^2-c-14=2c
The zeros of c^2-c-14=2c are c=(3+sqrt(65))/2 ,c=(3-sqrt(65))/2