What are the solutions to the equation 2x^2-7x=12 ?

The solutions to the equation 2x^2-7x=12 are x=(7+sqrt(145))/4 ,x=(7-sqrt(145))/4

Find the zeros of 2x^2-7x=12

The zeros of 2x^2-7x=12 are x=(7+sqrt(145))/4 ,x=(7-sqrt(145))/4

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2 x^{2} - 7 x = 12

x = \frac{7 + 145}{4}, x = \frac{7 - 145}{4}

Solution steps

2 x^{2} - 7 x = 12

Move

12

to the left side

2 x^{2} - 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 12) = 145

x_{1, 2} = \frac{- ( - 7 ) \pm 145}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 145}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 145}{2 \cdot 2}

x = \frac{- ( - 7 ) + 145}{2 \cdot 2} : \frac{7 + 145}{4}

x = \frac{- ( - 7 ) - 145}{2 \cdot 2} : \frac{7 - 145}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 145}{4}, x = \frac{7 - 145}{4}

6 x^{2} + 8 = - 16

x^{2} - 2 x - 1 = - 1

2 q^{2} + q - 1596 = 0

x, T (x) = x^{2} + 30 x + 200

x^{2} + 2 x + (- 15) = 0

What are the solutions to the equation 2x^2-7x=12 ?
The solutions to the equation 2x^2-7x=12 are x=(7+sqrt(145))/4 ,x=(7-sqrt(145))/4
Find the zeros of 2x^2-7x=12
The zeros of 2x^2-7x=12 are x=(7+sqrt(145))/4 ,x=(7-sqrt(145))/4