What are the solutions to the equation (4x+9)^2=36 ?

The solutions to the equation (4x+9)^2=36 are x=-3/4 ,x=-15/4

Find the zeros of (4x+9)^2=36

The zeros of (4x+9)^2=36 are x=-3/4 ,x=-15/4

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(4 x + 9)^{2} = 36

x = - \frac{3}{4}, x = - \frac{15}{4}

Solution steps

(4 x + 9)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 9 = 36 : x = - \frac{3}{4}

Solve

4 x + 9 = - 36 : x = - \frac{15}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - \frac{15}{4}

x, y^{3} - 5 y = 4 x - x^{2} + 9

x^{2} + 5 x = 104

- 5 x^{2} + 80 x - 320 = 0

25 x^{2} - 44 x + 380 = 0

\frac{2 x}{7} = 2 x^{2}

What are the solutions to the equation (4x+9)^2=36 ?
The solutions to the equation (4x+9)^2=36 are x=-3/4 ,x=-15/4
Find the zeros of (4x+9)^2=36
The zeros of (4x+9)^2=36 are x=-3/4 ,x=-15/4