What are the solutions to the equation -5x^2+80x-320=0 ?

The solutions to the equation -5x^2+80x-320=0 are x=8

Find the zeros of -5x^2+80x-320=0

The zeros of -5x^2+80x-320=0 are x=8

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- 5 x^{2} + 80 x - 320 = 0

x = 8

Solution steps

- 5 x^{2} + 80 x - 320 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 5 ) ( - 320 )}{2 ( - 5 )}

8 0^{2} - 4 (- 5) (- 320) = 0

x_{1, 2} = \frac{- 80 \pm 0}{2 ( - 5 )}

x = \frac{- 80}{2 ( - 5 )}

\frac{- 80}{2 ( - 5 )} = 8

x = 8

The solution to the quadratic equation is:

x = 8

25 x^{2} - 44 x + 380 = 0

\frac{2 x}{7} = 2 x^{2}

4 v^{2} + 720 = 0

2 x - 4 = (x + 1) (2 x - 4) - 5 (x + 1)

10 y^{2} - 25 y = 0

What are the solutions to the equation -5x^2+80x-320=0 ?
The solutions to the equation -5x^2+80x-320=0 are x=8
Find the zeros of -5x^2+80x-320=0
The zeros of -5x^2+80x-320=0 are x=8