What are the solutions to the equation 10y^2-25y=0 ?

The solutions to the equation 10y^2-25y=0 are y= 5/2 ,y=0

Find the zeros of 10y^2-25y=0

The zeros of 10y^2-25y=0 are y= 5/2 ,y=0

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10 y^{2} - 25 y = 0

y = \frac{5}{2}, y = 0

Decimal Notation

y = 2.5, y = 0

Solution steps

10 y^{2} - 25 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 10 \cdot 0}{2 \cdot 10}

(- 25)^{2} - 4 \cdot 10 \cdot 0 = 25

y_{1, 2} = \frac{- ( - 25 ) \pm 25}{2 \cdot 10}

Separate the solutions

y_{1} = \frac{- ( - 25 ) + 25}{2 \cdot 10}, y_{2} = \frac{- ( - 25 ) - 25}{2 \cdot 10}

y = \frac{- ( - 25 ) + 25}{2 \cdot 10} : \frac{5}{2}

y = \frac{- ( - 25 ) - 25}{2 \cdot 10} : 0

The solutions to the quadratic equation are:

y = \frac{5}{2}, y = 0

x^{2} = 7^{2} + 8^{2}

0 = 3 x^{2} - 8 x - 3

\frac{1}{2} x^{2} - 2 x - 6 = 0

y + 1 = \frac{y ^{2} - 6}{2}

(1 - x)^{2} - 2 = 0

What are the solutions to the equation 10y^2-25y=0 ?
The solutions to the equation 10y^2-25y=0 are y= 5/2 ,y=0
Find the zeros of 10y^2-25y=0
The zeros of 10y^2-25y=0 are y= 5/2 ,y=0