What are the solutions to the equation 0=3x^2-8x-3 ?

The solutions to the equation 0=3x^2-8x-3 are x=3,x=-1/3

Find the zeros of 0=3x^2-8x-3

The zeros of 0=3x^2-8x-3 are x=3,x=-1/3

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0 = 3 x^{2} - 8 x - 3

x = 3, x = - \frac{1}{3}

Decimal Notation

x = 3, x = - 0.33333 \dots

Solution steps

0 = 3 x^{2} - 8 x - 3

Switch sides

3 x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 3) = 10

x_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 3}

x = \frac{- ( - 8 ) + 10}{2 \cdot 3} : 3

x = \frac{- ( - 8 ) - 10}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{3}

\frac{1}{2} x^{2} - 2 x - 6 = 0

y + 1 = \frac{y ^{2} - 6}{2}

(1 - x)^{2} - 2 = 0

x^{2} - 49 = (x + 7)

2 a x^{2} - b x + a^{2} b^{2} = 0

What are the solutions to the equation 0=3x^2-8x-3 ?
The solutions to the equation 0=3x^2-8x-3 are x=3,x=-1/3
Find the zeros of 0=3x^2-8x-3
The zeros of 0=3x^2-8x-3 are x=3,x=-1/3