What are the solutions to the equation (1-x)^2-sqrt(2)=0 ?

The solutions to the equation (1-x)^2-sqrt(2)=0 are x=-\sqrt[4]{2}+1,x=1+\sqrt[4]{2}

Find the zeros of (1-x)^2-sqrt(2)=0

The zeros of (1-x)^2-sqrt(2)=0 are x=-\sqrt[4]{2}+1,x=1+\sqrt[4]{2}

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(1 - x)^{2} - 2 = 0

Decimal Notation

x = - 0.18920 \dots, x = 2.18920 \dots

Solution steps

(1 - x)^{2} - 2 = 0

Move

2

to the right side

(1 - x)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

The solutions to the quadratic equation are:

x^{2} - 49 = (x + 7)

2 a x^{2} - b x + a^{2} b^{2} = 0

n^{2} + 14 n - 5 = 0

x^{2} = 10 x - 20

x^{2} = 10 x - 10

What are the solutions to the equation (1-x)^2-sqrt(2)=0 ?
The solutions to the equation (1-x)^2-sqrt(2)=0 are x=-\sqrt[4]{2}+1,x=1+\sqrt[4]{2}
Find the zeros of (1-x)^2-sqrt(2)=0
The zeros of (1-x)^2-sqrt(2)=0 are x=-\sqrt[4]{2}+1,x=1+\sqrt[4]{2}