What are the solutions to the equation x^2=10x-20 ?

The solutions to the equation x^2=10x-20 are x=5+sqrt(5),x=5-sqrt(5)

Find the zeros of x^2=10x-20

The zeros of x^2=10x-20 are x=5+sqrt(5),x=5-sqrt(5)

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x^{2} = 10 x - 20

x = 5 + 5, x = 5 - 5

Solution steps

x^{2} = 10 x - 20

Move

20

to the left side

x^{2} + 20 = 10 x

Move

10 x

to the left side

x^{2} + 20 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 20 = 25

x_{1, 2} = \frac{- ( - 10 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 5}{2 \cdot 1} : 5 + 5

x = \frac{- ( - 10 ) - 2 5}{2 \cdot 1} : 5 - 5

The solutions to the quadratic equation are:

x = 5 + 5, x = 5 - 5

x^{2} = 10 x - 10

25 - 16 x^{2} = 0

x, p = 3 (y + 2 x)^{2}

x, 3 x^{2} y = 75

4 x^{2} + 16 x + 8

What are the solutions to the equation x^2=10x-20 ?
The solutions to the equation x^2=10x-20 are x=5+sqrt(5),x=5-sqrt(5)
Find the zeros of x^2=10x-20
The zeros of x^2=10x-20 are x=5+sqrt(5),x=5-sqrt(5)