What are the solutions to the equation ax^2-x=0 ?

The solutions to the equation ax^2-x=0 are x= 1/a ,x=0;\quad a\ne 0

Find the zeros of ax^2-x=0

The zeros of ax^2-x=0 are x= 1/a ,x=0;\quad a\ne 0

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a x^{2} - x = 0

x = \frac{1}{a}, x = 0; a \neq = 0

Solution steps

a x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 a \cdot 0}{2 a}

(- 1)^{2} - 4 a \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 a}, x_{2} = \frac{- ( - 1 ) - 1}{2 a}

x = \frac{- ( - 1 ) + 1}{2 a} : \frac{1}{a}

x = \frac{- ( - 1 ) - 1}{2 a} : 0

The solutions to the quadratic equation are:

x = \frac{1}{a}, x = 0; a \neq = 0

\frac{x ^{2}}{5} = x

- 2 x^{2} + 6 x - 8 = 0

x^{2} - x + 64 = 0

3 x^{2} - 6 x - 5 = 0

1 - x + 0.25 x^{2} = 0

What are the solutions to the equation ax^2-x=0 ?
The solutions to the equation ax^2-x=0 are x= 1/a ,x=0;\quad a\ne 0
Find the zeros of ax^2-x=0
The zeros of ax^2-x=0 are x= 1/a ,x=0;\quad a\ne 0