What are the solutions to the equation 1-x+0.25x^2=0 ?

The solutions to the equation 1-x+0.25x^2=0 are x=2

Find the zeros of 1-x+0.25x^2=0

The zeros of 1-x+0.25x^2=0 are x=2

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1 - x + 0.25 x^{2} = 0

x = 2

Solution steps

1 - x + 0.25 x^{2} = 0

Multiply both sides by

100

100 - 100 x + 25 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} - 100 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 100 ) \pm ( - 100 ) ^{2} - 4 \cdot 25 \cdot 100}{2 \cdot 25}

(- 100)^{2} - 4 \cdot 25 \cdot 100 = 0

x_{1, 2} = \frac{- ( - 100 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 100 )}{2 \cdot 25}

\frac{- ( - 100 )}{2 \cdot 25} = 2

x = 2

The solution to the quadratic equation is:

x = 2

6 x^{2} - 23 x = 0

x^{2} - 6 x - 4

x^{2} + x - 6 = - 4

x^{2} + 7 x + 3 = 33

9 x^{2} + 6 x = - 15

What are the solutions to the equation 1-x+0.25x^2=0 ?
The solutions to the equation 1-x+0.25x^2=0 are x=2
Find the zeros of 1-x+0.25x^2=0
The zeros of 1-x+0.25x^2=0 are x=2