What are the solutions to the equation x^2+7x+3=33 ?

The solutions to the equation x^2+7x+3=33 are x=3,x=-10

Find the zeros of x^2+7x+3=33

The zeros of x^2+7x+3=33 are x=3,x=-10

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x^{2} + 7 x + 3 = 33

x = 3, x = - 10

Solution steps

x^{2} + 7 x + 3 = 33

Move

33

to the left side

x^{2} + 7 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 30) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 1}, x_{2} = \frac{- 7 - 13}{2 \cdot 1}

x = \frac{- 7 + 13}{2 \cdot 1} : 3

x = \frac{- 7 - 13}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 3, x = - 10

9 x^{2} + 6 x = - 15

3 (z + 11)^{2} - 10 = 110

3 b^{2} - 7 b - 10 = 0

x^{2} - 16 x - 48 = 0

x^{2} + 3 x - 5 = 4 x + 3

What are the solutions to the equation x^2+7x+3=33 ?
The solutions to the equation x^2+7x+3=33 are x=3,x=-10
Find the zeros of x^2+7x+3=33
The zeros of x^2+7x+3=33 are x=3,x=-10