What are the solutions to the equation 3(z+11)^2-10=110 ?

The solutions to the equation 3(z+11)^2-10=110 are z=2sqrt(10)-11,z=-2sqrt(10)-11

Find the zeros of 3(z+11)^2-10=110

The zeros of 3(z+11)^2-10=110 are z=2sqrt(10)-11,z=-2sqrt(10)-11

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3 (z + 11)^{2} - 10 = 110

z = 210 - 11, z = - 210 - 11

Decimal Notation

z = - 4.67544 \dots, z = - 17.32455 \dots

Solution steps

3 (z + 11)^{2} - 10 = 110

Move

10

to the right side

3 (z + 11)^{2} = 120

Divide both sides by

3

(z + 11)^{2} = 40

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 11 = 40 : z = 210 - 11

Solve

z + 11 = - 40 : z = - 210 - 11

The solutions to the quadratic equation are:

z = 210 - 11, z = - 210 - 11

3 b^{2} - 7 b - 10 = 0

x^{2} - 16 x - 48 = 0

x^{2} + 3 x - 5 = 4 x + 3

3 x^{2} - 6 x - 2 = 0

64 = r^{2}

What are the solutions to the equation 3(z+11)^2-10=110 ?
The solutions to the equation 3(z+11)^2-10=110 are z=2sqrt(10)-11,z=-2sqrt(10)-11
Find the zeros of 3(z+11)^2-10=110
The zeros of 3(z+11)^2-10=110 are z=2sqrt(10)-11,z=-2sqrt(10)-11