What are the solutions to the equation completesquare 3x^2-6x-2=0 ?

The solutions to the equation completesquare 3x^2-6x-2=0 are x=sqrt(5/3)+1,x=-sqrt(5/3)+1

Find the zeros of completesquare 3x^2-6x-2=0

The zeros of completesquare 3x^2-6x-2=0 are x=sqrt(5/3)+1,x=-sqrt(5/3)+1

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3 x^{2} - 6 x - 2 = 0

x = \frac{5}{3} + 1, x = - \frac{5}{3} + 1

Decimal Notation

x = 2.29099 \dots, x = - 0.29099 \dots

Solution steps

3 x^{2} - 6 x - 2 = 0

Move

2

to the right side

3 x^{2} - 6 x = 2

Divide both sides by

3

\frac{3 x ^{2} - 6 x}{3} = \frac{2}{3}

x^{2} - 2 x = \frac{2}{3}

Rewrite in the form

(x + a)^{2} = b

(x - 1)^{2} = \frac{5}{3}

For

the solutions are

f (x) = a, - a

Solve

x - 1 = \frac{5}{3} : x = \frac{5}{3} + 1

Solve

x - 1 = - \frac{5}{3} : x = - \frac{5}{3} + 1

The solutions to the quadratic equation are:

x = \frac{5}{3} + 1, x = - \frac{5}{3} + 1

64 = r^{2}

4 x^{2} + 9 = x^{2} + 60

4 u^{2} - 8 u + 3 = 0

4 x^{2} + 36 x + 73 = 0

- 6 x^{2} + 13 x + 8 = 0

What are the solutions to the equation completesquare 3x^2-6x-2=0 ?
The solutions to the equation completesquare 3x^2-6x-2=0 are x=sqrt(5/3)+1,x=-sqrt(5/3)+1
Find the zeros of completesquare 3x^2-6x-2=0
The zeros of completesquare 3x^2-6x-2=0 are x=sqrt(5/3)+1,x=-sqrt(5/3)+1