What are the solutions to the equation 4u^2-8u+3=0 ?

The solutions to the equation 4u^2-8u+3=0 are u= 3/2 ,u= 1/2

Find the zeros of 4u^2-8u+3=0

The zeros of 4u^2-8u+3=0 are u= 3/2 ,u= 1/2

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4 u^{2} - 8 u + 3 = 0

u = \frac{3}{2}, u = \frac{1}{2}

Decimal Notation

u = 1.5, u = 0.5

Solution steps

4 u^{2} - 8 u + 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 3 = 4

u_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 4}, u_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 4}

u = \frac{- ( - 8 ) + 4}{2 \cdot 4} : \frac{3}{2}

u = \frac{- ( - 8 ) - 4}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

u = \frac{3}{2}, u = \frac{1}{2}

4 x^{2} + 36 x + 73 = 0

- 6 x^{2} + 13 x + 8 = 0

2 v^{2} + 16 v + 36 = 0

x^{2} + x = 6

2 x^{2} + 7 x = x^{2} + 30

What are the solutions to the equation 4u^2-8u+3=0 ?
The solutions to the equation 4u^2-8u+3=0 are u= 3/2 ,u= 1/2
Find the zeros of 4u^2-8u+3=0
The zeros of 4u^2-8u+3=0 are u= 3/2 ,u= 1/2