What are the solutions to the equation 2v^2+16v+36=0 ?

The solutions to the equation 2v^2+16v+36=0 are v=-4+sqrt(2)i,v=-4-sqrt(2)i

Find the zeros of 2v^2+16v+36=0

The zeros of 2v^2+16v+36=0 are v=-4+sqrt(2)i,v=-4-sqrt(2)i

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2 v^{2} + 16 v + 36 = 0

v = - 4 + 2 i, v = - 4 - 2 i

Solution steps

2 v^{2} + 16 v + 36 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 \cdot 36}{2 \cdot 2}

Simplify

1 6^{2} - 4 \cdot 2 \cdot 36 : 42 i

v_{1, 2} = \frac{- 16 \pm 4 2 i}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- 16 + 4 2 i}{2 \cdot 2}, v_{2} = \frac{- 16 - 4 2 i}{2 \cdot 2}

v = \frac{- 16 + 4 2 i}{2 \cdot 2} : - 4 + 2 i

v = \frac{- 16 - 4 2 i}{2 \cdot 2} : - 4 - 2 i

The solutions to the quadratic equation are:

v = - 4 + 2 i, v = - 4 - 2 i

x^{2} + x = 6

2 x^{2} + 7 x = x^{2} + 30

x (3 x - 2) = x^{2} - 5 x

a^{2} - 3.4 a + 1.2 = 0

x^{2} - 7 x - 170 = 0

What are the solutions to the equation 2v^2+16v+36=0 ?
The solutions to the equation 2v^2+16v+36=0 are v=-4+sqrt(2)i,v=-4-sqrt(2)i
Find the zeros of 2v^2+16v+36=0
The zeros of 2v^2+16v+36=0 are v=-4+sqrt(2)i,v=-4-sqrt(2)i