What are the solutions to the equation 2x^2+7x=x^2+30 ?

The solutions to the equation 2x^2+7x=x^2+30 are x=3,x=-10

Find the zeros of 2x^2+7x=x^2+30

The zeros of 2x^2+7x=x^2+30 are x=3,x=-10

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2 x^{2} + 7 x = x^{2} + 30

x = 3, x = - 10

Solution steps

2 x^{2} + 7 x = x^{2} + 30

Move

30

to the left side

2 x^{2} + 7 x - 30 = x^{2}

Move

x^{2}

to the left side

x^{2} + 7 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 30) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 1}, x_{2} = \frac{- 7 - 13}{2 \cdot 1}

x = \frac{- 7 + 13}{2 \cdot 1} : 3

x = \frac{- 7 - 13}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 3, x = - 10

x (3 x - 2) = x^{2} - 5 x

a^{2} - 3.4 a + 1.2 = 0

x^{2} - 7 x - 170 = 0

2 x^{2} - 7 x - 32 = 0

2 x^{2} + 5 x - 14 = 0

What are the solutions to the equation 2x^2+7x=x^2+30 ?
The solutions to the equation 2x^2+7x=x^2+30 are x=3,x=-10
Find the zeros of 2x^2+7x=x^2+30
The zeros of 2x^2+7x=x^2+30 are x=3,x=-10