What are the solutions to the equation 2x^2+5x-14=0 ?

The solutions to the equation 2x^2+5x-14=0 are x=(-5+sqrt(137))/4 ,x=(-5-sqrt(137))/4

Find the zeros of 2x^2+5x-14=0

The zeros of 2x^2+5x-14=0 are x=(-5+sqrt(137))/4 ,x=(-5-sqrt(137))/4

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2 x^{2} + 5 x - 14 = 0

x = \frac{- 5 + 137}{4}, x = \frac{- 5 - 137}{4}

Decimal Notation

x = 1.67617 \dots, x = - 4.17617 \dots

Solution steps

2 x^{2} + 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 14) = 137

x_{1, 2} = \frac{- 5 \pm 137}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 137}{2 \cdot 2}, x_{2} = \frac{- 5 - 137}{2 \cdot 2}

x = \frac{- 5 + 137}{2 \cdot 2} : \frac{- 5 + 137}{4}

x = \frac{- 5 - 137}{2 \cdot 2} : \frac{- 5 - 137}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 137}{4}, x = \frac{- 5 - 137}{4}

x^{2} - 5 x + 2 = 3 - 2 x

r^{2} - \frac{4}{9} = 0

- 4 v^{2} + 8 v - 4 = 0

2 (2 u^{2} - 4 u) + 3 = 0

c^{2} = 4

What are the solutions to the equation 2x^2+5x-14=0 ?
The solutions to the equation 2x^2+5x-14=0 are x=(-5+sqrt(137))/4 ,x=(-5-sqrt(137))/4
Find the zeros of 2x^2+5x-14=0
The zeros of 2x^2+5x-14=0 are x=(-5+sqrt(137))/4 ,x=(-5-sqrt(137))/4