What are the solutions to the equation x^2-5x+2=3-2x ?

The solutions to the equation x^2-5x+2=3-2x are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2

Find the zeros of x^2-5x+2=3-2x

The zeros of x^2-5x+2=3-2x are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2

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x^{2} - 5 x + 2 = 3 - 2 x

x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

Decimal Notation

x = 3.30277 \dots, x = - 0.30277 \dots

Solution steps

x^{2} - 5 x + 2 = 3 - 2 x

Move

2 x

to the left side

x^{2} - 3 x + 2 = 3

Move

3

to the left side

x^{2} - 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 1) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

x = \frac{- ( - 3 ) + 13}{2 \cdot 1} : \frac{3 + 13}{2}

x = \frac{- ( - 3 ) - 13}{2 \cdot 1} : \frac{3 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

r^{2} - \frac{4}{9} = 0

- 4 v^{2} + 8 v - 4 = 0

2 (2 u^{2} - 4 u) + 3 = 0

c^{2} = 4

x^{2} + 2 x = 300

What are the solutions to the equation x^2-5x+2=3-2x ?
The solutions to the equation x^2-5x+2=3-2x are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2
Find the zeros of x^2-5x+2=3-2x
The zeros of x^2-5x+2=3-2x are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2