What are the solutions to the equation -4v^2+8v-4=0 ?

The solutions to the equation -4v^2+8v-4=0 are v=1

Find the zeros of -4v^2+8v-4=0

The zeros of -4v^2+8v-4=0 are v=1

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- 4 v^{2} + 8 v - 4 = 0

v = 1

Solution steps

- 4 v^{2} + 8 v - 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) ( - 4 )}{2 ( - 4 )}

8^{2} - 4 (- 4) (- 4) = 0

v_{1, 2} = \frac{- 8 \pm 0}{2 ( - 4 )}

v = \frac{- 8}{2 ( - 4 )}

\frac{- 8}{2 ( - 4 )} = 1

v = 1

The solution to the quadratic equation is:

v = 1

2 (2 u^{2} - 4 u) + 3 = 0

c^{2} = 4

x^{2} + 2 x = 300

2 x^{2} + 5 x - 11 = 0

5 x^{2} - 4 x - 8 = 0

What are the solutions to the equation -4v^2+8v-4=0 ?
The solutions to the equation -4v^2+8v-4=0 are v=1
Find the zeros of -4v^2+8v-4=0
The zeros of -4v^2+8v-4=0 are v=1