What are the solutions to the equation 5x^2-4x-8=0 ?

The solutions to the equation 5x^2-4x-8=0 are x=(2(1+sqrt(11)))/5 ,x=(2(1-sqrt(11)))/5

Find the zeros of 5x^2-4x-8=0

The zeros of 5x^2-4x-8=0 are x=(2(1+sqrt(11)))/5 ,x=(2(1-sqrt(11)))/5

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5 x^{2} - 4 x - 8 = 0

x = \frac{2 ( 1 + 11 )}{5}, x = \frac{2 ( 1 - 11 )}{5}

Decimal Notation

x = 1.72664 \dots, x = - 0.92664 \dots

Solution steps

5 x^{2} - 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 8) = 411

x_{1, 2} = \frac{- ( - 4 ) \pm 4 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 11}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 4 11}{2 \cdot 5}

x = \frac{- ( - 4 ) + 4 11}{2 \cdot 5} : \frac{2 ( 1 + 11 )}{5}

x = \frac{- ( - 4 ) - 4 11}{2 \cdot 5} : \frac{2 ( 1 - 11 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 1 + 11 )}{5}, x = \frac{2 ( 1 - 11 )}{5}

0.3 x^{2} - 1.2 x - 0.3 = 0

\frac{3}{8} x^{2} + 3 x + 24 = 0

x, x^{2} y - x^{2} - y = 0

4 x^{2} - 32 x + 8 = 12

5 x - x^{2} - x = 0

What are the solutions to the equation 5x^2-4x-8=0 ?
The solutions to the equation 5x^2-4x-8=0 are x=(2(1+sqrt(11)))/5 ,x=(2(1-sqrt(11)))/5
Find the zeros of 5x^2-4x-8=0
The zeros of 5x^2-4x-8=0 are x=(2(1+sqrt(11)))/5 ,x=(2(1-sqrt(11)))/5