What are the solutions to the equation 2x^2+sqrt(12)x+2=0 ?

The solutions to the equation 2x^2+sqrt(12)x+2=0 are x=-(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2-i 1/2

Find the zeros of 2x^2+sqrt(12)x+2=0

The zeros of 2x^2+sqrt(12)x+2=0 are x=-(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2-i 1/2

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2 x^{2} + 12 x + 2 = 0

x = - \frac{3}{2} + i \frac{1}{2}, x = - \frac{3}{2} - i \frac{1}{2}

Solution steps

2 x^{2} + 12 x + 2 = 0

Refine

2 x^{2} + 23 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 3 \pm ( 2 3 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

Simplify

(23)^{2} - 4 \cdot 2 \cdot 2 : 2 i

x_{1, 2} = \frac{- 2 3 \pm 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 3 + 2 i}{2 \cdot 2}, x_{2} = \frac{- 2 3 - 2 i}{2 \cdot 2}

x = \frac{- 2 3 + 2 i}{2 \cdot 2} : - \frac{3}{2} + i \frac{1}{2}

x = \frac{- 2 3 - 2 i}{2 \cdot 2} : - \frac{3}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{1}{2}, x = - \frac{3}{2} - i \frac{1}{2}

(x - 1)^{2} + (x + 4)^{2} = 5

x^{2} = 12 x - 36

1 6^{2} + 6 3^{2} = c^{2}

9 x^{2} + 18 x + 17 = 0

- 2 x^{2} = 5 x + 2

What are the solutions to the equation 2x^2+sqrt(12)x+2=0 ?
The solutions to the equation 2x^2+sqrt(12)x+2=0 are x=-(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2-i 1/2
Find the zeros of 2x^2+sqrt(12)x+2=0
The zeros of 2x^2+sqrt(12)x+2=0 are x=-(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2-i 1/2