What are the solutions to the equation 9x^2+18x+17=0 ?

The solutions to the equation 9x^2+18x+17=0 are x=-1+i(2sqrt(2))/3 ,x=-1-i(2sqrt(2))/3

Find the zeros of 9x^2+18x+17=0

The zeros of 9x^2+18x+17=0 are x=-1+i(2sqrt(2))/3 ,x=-1-i(2sqrt(2))/3

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9 x^{2} + 18 x + 17 = 0

x = - 1 + i \frac{2 2}{3}, x = - 1 - i \frac{2 2}{3}

Solution steps

9 x^{2} + 18 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 17}{2 \cdot 9}

Simplify

1 8^{2} - 4 \cdot 9 \cdot 17 : 122 i

x_{1, 2} = \frac{- 18 \pm 12 2 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 12 2 i}{2 \cdot 9}, x_{2} = \frac{- 18 - 12 2 i}{2 \cdot 9}

x = \frac{- 18 + 12 2 i}{2 \cdot 9} : - 1 + i \frac{2 2}{3}

x = \frac{- 18 - 12 2 i}{2 \cdot 9} : - 1 - i \frac{2 2}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{2 2}{3}, x = - 1 - i \frac{2 2}{3}

- 2 x^{2} = 5 x + 2

(x + 20) (x + 4) = 8 x - 1

2 x^{2} + 9 x + 9

5^{2} = (x + 1)^{2} + x^{2}

2 x^{2} + 9 x + 4

What are the solutions to the equation 9x^2+18x+17=0 ?
The solutions to the equation 9x^2+18x+17=0 are x=-1+i(2sqrt(2))/3 ,x=-1-i(2sqrt(2))/3
Find the zeros of 9x^2+18x+17=0
The zeros of 9x^2+18x+17=0 are x=-1+i(2sqrt(2))/3 ,x=-1-i(2sqrt(2))/3