What are the solutions to the equation x^2+5x-6=0 ?

The solutions to the equation x^2+5x-6=0 are x=1,x=-6

Find the zeros of x^2+5x-6=0

The zeros of x^2+5x-6=0 are x=1,x=-6

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x^{2} + 5 x - 6 = 0

x = 1, x = - 6

Solution steps

x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 1}, x_{2} = \frac{- 5 - 7}{2 \cdot 1}

x = \frac{- 5 + 7}{2 \cdot 1} : 1

x = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

u \cdot u^{\frac{1}{2}}

2704

\frac{1}{a ^{5} a ^{- 4}}

4 x - 28 = 5 x \cdot (x - 7)

\frac{4 - 2 i}{4 + 6 i}

What are the solutions to the equation x^2+5x-6=0 ?
The solutions to the equation x^2+5x-6=0 are x=1,x=-6
Find the zeros of x^2+5x-6=0
The zeros of x^2+5x-6=0 are x=1,x=-6