What are the solutions to the equation (x+20)(x+4)=8x-1 ?

The solutions to the equation (x+20)(x+4)=8x-1 are x=-8+sqrt(17)i,x=-8-sqrt(17)i

Find the zeros of (x+20)(x+4)=8x-1

The zeros of (x+20)(x+4)=8x-1 are x=-8+sqrt(17)i,x=-8-sqrt(17)i

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(x + 20) (x + 4) = 8 x - 1

x = - 8 + 17 i, x = - 8 - 17 i

Solution steps

(x + 20) (x + 4) = 8 x - 1

Expand

(x + 20) (x + 4) : x^{2} + 24 x + 80

x^{2} + 24 x + 80 = 8 x - 1

Move

1

to the left side

x^{2} + 24 x + 81 = 8 x

Move

8 x

to the left side

x^{2} + 16 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot 81 : 217 i

x_{1, 2} = \frac{- 16 \pm 2 17 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 17 i}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 17 i}{2 \cdot 1}

x = \frac{- 16 + 2 17 i}{2 \cdot 1} : - 8 + 17 i

x = \frac{- 16 - 2 17 i}{2 \cdot 1} : - 8 - 17 i

The solutions to the quadratic equation are:

x = - 8 + 17 i, x = - 8 - 17 i

2 x^{2} + 9 x + 9

5^{2} = (x + 1)^{2} + x^{2}

2 x^{2} + 9 x + 4

8 x^{2} - 2 (x + 10) = 10 x

(2 x + 1) (x - 2) = 5

What are the solutions to the equation (x+20)(x+4)=8x-1 ?
The solutions to the equation (x+20)(x+4)=8x-1 are x=-8+sqrt(17)i,x=-8-sqrt(17)i
Find the zeros of (x+20)(x+4)=8x-1
The zeros of (x+20)(x+4)=8x-1 are x=-8+sqrt(17)i,x=-8-sqrt(17)i