What are the solutions to the equation 8x^2-2(x+10)=10x ?

The solutions to the equation 8x^2-2(x+10)=10x are x= 5/2 ,x=-1

Find the zeros of 8x^2-2(x+10)=10x

The zeros of 8x^2-2(x+10)=10x are x= 5/2 ,x=-1

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8 x^{2} - 2 (x + 10) = 10 x

x = \frac{5}{2}, x = - 1

Decimal Notation

x = 2.5, x = - 1

Solution steps

8 x^{2} - 2 (x + 10) = 10 x

Expand

8 x^{2} - 2 (x + 10) : 8 x^{2} - 2 x - 20

8 x^{2} - 2 x - 20 = 10 x

Move

10 x

to the left side

8 x^{2} - 12 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 8 ( - 20 )}{2 \cdot 8}

(- 12)^{2} - 4 \cdot 8 (- 20) = 28

x_{1, 2} = \frac{- ( - 12 ) \pm 28}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 28}{2 \cdot 8}, x_{2} = \frac{- ( - 12 ) - 28}{2 \cdot 8}

x = \frac{- ( - 12 ) + 28}{2 \cdot 8} : \frac{5}{2}

x = \frac{- ( - 12 ) - 28}{2 \cdot 8} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 1

(2 x + 1) (x - 2) = 5

x, x^{2} + y^{2} + 18 = 0

8 = 3 x^{2} - 2 x

2 x (x + 2) = 0

(x + 5)^{2} = 29

What are the solutions to the equation 8x^2-2(x+10)=10x ?
The solutions to the equation 8x^2-2(x+10)=10x are x= 5/2 ,x=-1
Find the zeros of 8x^2-2(x+10)=10x
The zeros of 8x^2-2(x+10)=10x are x= 5/2 ,x=-1