What are the solutions to the equation (x+5)^2=29 ?

The solutions to the equation (x+5)^2=29 are x=sqrt(29)-5,x=-sqrt(29)-5

Find the zeros of (x+5)^2=29

The zeros of (x+5)^2=29 are x=sqrt(29)-5,x=-sqrt(29)-5

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(x + 5)^{2} = 29

x = 29 - 5, x = - 29 - 5

Decimal Notation

x = 0.38516 \dots, x = - 10.38516 \dots

Solution steps

(x + 5)^{2} = 29

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 29 : x = 29 - 5

Solve

x + 5 = - 29 : x = - 29 - 5

The solutions to the quadratic equation are:

x = 29 - 5, x = - 29 - 5

2 x^{2} + 5 x - 3 = x^{2} - x + 13

7 m^{2} - 27 m + 18 = 0

4 x \cdot 3 x = 3072

4 x (3 + 5 x) = 0

y^{2} + y = 3

What are the solutions to the equation (x+5)^2=29 ?
The solutions to the equation (x+5)^2=29 are x=sqrt(29)-5,x=-sqrt(29)-5
Find the zeros of (x+5)^2=29
The zeros of (x+5)^2=29 are x=sqrt(29)-5,x=-sqrt(29)-5