What are the solutions to the equation -90x^2+1530x-6300=0 ?

The solutions to the equation -90x^2+1530x-6300=0 are x=7,x=10

Find the zeros of -90x^2+1530x-6300=0

The zeros of -90x^2+1530x-6300=0 are x=7,x=10

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- 90 x^{2} + 1530 x - 6300 = 0

x = 7, x = 10

Solution steps

- 90 x^{2} + 1530 x - 6300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1530 \pm 153 0 ^{2} - 4 ( - 90 ) ( - 6300 )}{2 ( - 90 )}

153 0^{2} - 4 (- 90) (- 6300) = 270

x_{1, 2} = \frac{- 1530 \pm 270}{2 ( - 90 )}

Separate the solutions

x_{1} = \frac{- 1530 + 270}{2 ( - 90 )}, x_{2} = \frac{- 1530 - 270}{2 ( - 90 )}

x = \frac{- 1530 + 270}{2 ( - 90 )} : 7

x = \frac{- 1530 - 270}{2 ( - 90 )} : 10

The solutions to the quadratic equation are:

x = 7, x = 10

300 = x^{2} + 2 x

0 = (x - 5)^{2} + 4 (x - 5) + 4

8 n^{2} - 3 = 37

5 x^{2} - 5 = x

m^{2} + 4 m = 32

What are the solutions to the equation -90x^2+1530x-6300=0 ?
The solutions to the equation -90x^2+1530x-6300=0 are x=7,x=10
Find the zeros of -90x^2+1530x-6300=0
The zeros of -90x^2+1530x-6300=0 are x=7,x=10