What are the solutions to the equation 300=x^2+2x ?

The solutions to the equation 300=x^2+2x are x=-1+sqrt(301),x=-1-sqrt(301)

Find the zeros of 300=x^2+2x

The zeros of 300=x^2+2x are x=-1+sqrt(301),x=-1-sqrt(301)

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300 = x^{2} + 2 x

x = - 1 + 301, x = - 1 - 301

Decimal Notation

x = 16.34935 \dots, x = - 18.34935 \dots

Solution steps

300 = x^{2} + 2 x

Switch sides

x^{2} + 2 x = 300

Move

300

to the left side

x^{2} + 2 x - 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 300 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 300) = 2301

x_{1, 2} = \frac{- 2 \pm 2 301}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 301}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 301}{2 \cdot 1}

x = \frac{- 2 + 2 301}{2 \cdot 1} : - 1 + 301

x = \frac{- 2 - 2 301}{2 \cdot 1} : - 1 - 301

The solutions to the quadratic equation are:

x = - 1 + 301, x = - 1 - 301

0 = (x - 5)^{2} + 4 (x - 5) + 4

8 n^{2} - 3 = 37

5 x^{2} - 5 = x

m^{2} + 4 m = 32

5 x^{2} - 4 = x

What are the solutions to the equation 300=x^2+2x ?
The solutions to the equation 300=x^2+2x are x=-1+sqrt(301),x=-1-sqrt(301)
Find the zeros of 300=x^2+2x
The zeros of 300=x^2+2x are x=-1+sqrt(301),x=-1-sqrt(301)