What are the solutions to the equation 5x^2-4=x ?

The solutions to the equation 5x^2-4=x are x=1,x=-4/5

Find the zeros of 5x^2-4=x

The zeros of 5x^2-4=x are x=1,x=-4/5

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5 x^{2} - 4 = x

x = 1, x = - \frac{4}{5}

Decimal Notation

x = 1, x = - 0.8

Solution steps

5 x^{2} - 4 = x

Move

x

to the left side

5 x^{2} - 4 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 4) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 5}

x = \frac{- ( - 1 ) + 9}{2 \cdot 5} : 1

x = \frac{- ( - 1 ) - 9}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{5}

y, s (y) = 3 yy + 5

2 y^{2} + 2 y - 4 = 0

20 x^{2} + 4 x = 0

(0 - 2)^{2} - (y - 1)^{2} = 9

0.25 x^{2} - 350 x - 100000 = 0

What are the solutions to the equation 5x^2-4=x ?
The solutions to the equation 5x^2-4=x are x=1,x=-4/5
Find the zeros of 5x^2-4=x
The zeros of 5x^2-4=x are x=1,x=-4/5