What are the solutions to the equation 20x^2+4x=0 ?

The solutions to the equation 20x^2+4x=0 are x=0,x=-1/5

Find the zeros of 20x^2+4x=0

The zeros of 20x^2+4x=0 are x=0,x=-1/5

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20 x^{2} + 4 x = 0

x = 0, x = - \frac{1}{5}

Decimal Notation

x = 0, x = - 0.2

Solution steps

20 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 20 \cdot 0}{2 \cdot 20}

4^{2} - 4 \cdot 20 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 20}, x_{2} = \frac{- 4 - 4}{2 \cdot 20}

x = \frac{- 4 + 4}{2 \cdot 20} : 0

x = \frac{- 4 - 4}{2 \cdot 20} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{5}

(0 - 2)^{2} - (y - 1)^{2} = 9

0.25 x^{2} - 350 x - 100000 = 0

1 - 3 x - 2 x^{2} = 0

8^{2} + 6^{2} = X^{2}

3 y^{2} - 2 y - 4 = 0

What are the solutions to the equation 20x^2+4x=0 ?
The solutions to the equation 20x^2+4x=0 are x=0,x=-1/5
Find the zeros of 20x^2+4x=0
The zeros of 20x^2+4x=0 are x=0,x=-1/5