What are the solutions to the equation 3+x-2x^2=0 ?

The solutions to the equation 3+x-2x^2=0 are x=-1,x= 3/2

Find the zeros of 3+x-2x^2=0

The zeros of 3+x-2x^2=0 are x=-1,x= 3/2

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3 + x - 2 x^{2} = 0

x = - 1, x = \frac{3}{2}

Decimal Notation

x = - 1, x = 1.5

Solution steps

3 + x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 3 = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 ( - 2 )}, x_{2} = \frac{- 1 - 5}{2 ( - 2 )}

x = \frac{- 1 + 5}{2 ( - 2 )} : - 1

x = \frac{- 1 - 5}{2 ( - 2 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{3}{2}

\frac{3 x ^{2}}{2} = 0

5 x^{2} - 2 = 23

r^{2} = 24

x^{2} = - 7 x + 2

x^{2} - x + 2 = 0

What are the solutions to the equation 3+x-2x^2=0 ?
The solutions to the equation 3+x-2x^2=0 are x=-1,x= 3/2
Find the zeros of 3+x-2x^2=0
The zeros of 3+x-2x^2=0 are x=-1,x= 3/2