What are the solutions to the equation x^2=-7x+2 ?

The solutions to the equation x^2=-7x+2 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2

Find the zeros of x^2=-7x+2

The zeros of x^2=-7x+2 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2

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x^{2} = - 7 x + 2

x = \frac{- 7 + 57}{2}, x = \frac{- 7 - 57}{2}

Decimal Notation

x = 0.27491 \dots, x = - 7.27491 \dots

Solution steps

x^{2} = - 7 x + 2

Move

2

to the left side

x^{2} - 2 = - 7 x

Move

7 x

to the left side

x^{2} - 2 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 2) = 57

x_{1, 2} = \frac{- 7 \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 57}{2 \cdot 1}, x_{2} = \frac{- 7 - 57}{2 \cdot 1}

x = \frac{- 7 + 57}{2 \cdot 1} : \frac{- 7 + 57}{2}

x = \frac{- 7 - 57}{2 \cdot 1} : \frac{- 7 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 57}{2}, x = \frac{- 7 - 57}{2}

x^{2} - x + 2 = 0

2 x^{2} + x = 1

2 y^{2} + 2 y - 2 = 0

x = x^{2} + 3 x - 2

x^{2} = 64

What are the solutions to the equation x^2=-7x+2 ?
The solutions to the equation x^2=-7x+2 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2
Find the zeros of x^2=-7x+2
The zeros of x^2=-7x+2 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2