What are the solutions to the equation 4b^2+16b-19=-10 ?

The solutions to the equation 4b^2+16b-19=-10 are b= 1/2 ,b=-9/2

Find the zeros of 4b^2+16b-19=-10

The zeros of 4b^2+16b-19=-10 are b= 1/2 ,b=-9/2

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4 b^{2} + 16 b - 19 = - 10

b = \frac{1}{2}, b = - \frac{9}{2}

Decimal Notation

b = 0.5, b = - 4.5

Solution steps

4 b^{2} + 16 b - 19 = - 10

Move

10

to the left side

4 b^{2} + 16 b - 9 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 (- 9) = 20

b_{1, 2} = \frac{- 16 \pm 20}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- 16 + 20}{2 \cdot 4}, b_{2} = \frac{- 16 - 20}{2 \cdot 4}

b = \frac{- 16 + 20}{2 \cdot 4} : \frac{1}{2}

b = \frac{- 16 - 20}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

b = \frac{1}{2}, b = - \frac{9}{2}

(x - 2) \cdot (x - 1) = 0

\frac{1}{2} x^{2} + 5 x - 12 = 0

(x + 1) (3 x - 5) = (5 x - 3) \cdot 4

r, z = r^{2}

0.25 [2.5 x + 1.5 (x - 4)] = - x \cdot x

What are the solutions to the equation 4b^2+16b-19=-10 ?
The solutions to the equation 4b^2+16b-19=-10 are b= 1/2 ,b=-9/2
Find the zeros of 4b^2+16b-19=-10
The zeros of 4b^2+16b-19=-10 are b= 1/2 ,b=-9/2