What are the solutions to the equation 1/2 x^2+5x-12=0 ?

The solutions to the equation 1/2 x^2+5x-12=0 are x=2,x=-12

Find the zeros of 1/2 x^2+5x-12=0

The zeros of 1/2 x^2+5x-12=0 are x=2,x=-12

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\frac{1}{2} x^{2} + 5 x - 12 = 0

x = 2, x = - 12

Solution steps

\frac{1}{2} x^{2} + 5 x - 12 = 0

Multiply both sides by

2

x^{2} + 10 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 24) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 1}, x_{2} = \frac{- 10 - 14}{2 \cdot 1}

x = \frac{- 10 + 14}{2 \cdot 1} : 2

x = \frac{- 10 - 14}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 2, x = - 12

(x + 1) (3 x - 5) = (5 x - 3) \cdot 4

r, z = r^{2}

0.25 [2.5 x + 1.5 (x - 4)] = - x \cdot x

2 y (3 - y) = 7

x^{2} - 4 x + 4 = - 25

What are the solutions to the equation 1/2 x^2+5x-12=0 ?
The solutions to the equation 1/2 x^2+5x-12=0 are x=2,x=-12
Find the zeros of 1/2 x^2+5x-12=0
The zeros of 1/2 x^2+5x-12=0 are x=2,x=-12