What are the solutions to the equation x^2+8x+36=-8x ?

The solutions to the equation x^2+8x+36=-8x are x=2(sqrt(7)-4),x=-2(4+sqrt(7))

Find the zeros of x^2+8x+36=-8x

The zeros of x^2+8x+36=-8x are x=2(sqrt(7)-4),x=-2(4+sqrt(7))

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x^{2} + 8 x + 36 = - 8 x

x = 2 (7 - 4), x = - 2 (4 + 7)

Decimal Notation

x = - 2.70849 \dots, x = - 13.29150 \dots

Solution steps

x^{2} + 8 x + 36 = - 8 x

Move

8 x

to the left side

x^{2} + 16 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 36 = 47

x_{1, 2} = \frac{- 16 \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4 7}{2 \cdot 1}, x_{2} = \frac{- 16 - 4 7}{2 \cdot 1}

x = \frac{- 16 + 4 7}{2 \cdot 1} : 2 (7 - 4)

x = \frac{- 16 - 4 7}{2 \cdot 1} : - 2 (4 + 7)

The solutions to the quadratic equation are:

x = 2 (7 - 4), x = - 2 (4 + 7)

9.81 x^{2} - 10 x - 88.2 = 0

x, y = 2 x^{2} + 3 x - 1

x^{2} + 2 x - 63 = 0

x^{2} - 20 x - 1 = - 20

6 b^{2} - 16 b - 92 = - 6 b

What are the solutions to the equation x^2+8x+36=-8x ?
The solutions to the equation x^2+8x+36=-8x are x=2(sqrt(7)-4),x=-2(4+sqrt(7))
Find the zeros of x^2+8x+36=-8x
The zeros of x^2+8x+36=-8x are x=2(sqrt(7)-4),x=-2(4+sqrt(7))