What are the solutions to the equation 105x^2+80=200x ?

The solutions to the equation 105x^2+80=200x are x= 4/3 ,x= 4/7

Find the zeros of 105x^2+80=200x

The zeros of 105x^2+80=200x are x= 4/3 ,x= 4/7

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105 x^{2} + 80 = 200 x

x = \frac{4}{3}, x = \frac{4}{7}

Decimal Notation

x = 1.33333 \dots, x = 0.57142 \dots

Solution steps

105 x^{2} + 80 = 200 x

Move

200 x

to the left side

105 x^{2} + 80 - 200 x = 0

Write in the standard form

a x^{2} + b x + c = 0

105 x^{2} - 200 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 105 \cdot 80}{2 \cdot 105}

(- 200)^{2} - 4 \cdot 105 \cdot 80 = 80

x_{1, 2} = \frac{- ( - 200 ) \pm 80}{2 \cdot 105}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 80}{2 \cdot 105}, x_{2} = \frac{- ( - 200 ) - 80}{2 \cdot 105}

x = \frac{- ( - 200 ) + 80}{2 \cdot 105} : \frac{4}{3}

x = \frac{- ( - 200 ) - 80}{2 \cdot 105} : \frac{4}{7}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = \frac{4}{7}

(9 z + 5)^{2} = 0

5 a^{2} - 6 a + 10 = 0

2 x^{2} - 26 x + 72 = 0

x^{2} = 8 (x + 6)

3 x^{2} + 26 x = 14 x + 135

What are the solutions to the equation 105x^2+80=200x ?
The solutions to the equation 105x^2+80=200x are x= 4/3 ,x= 4/7
Find the zeros of 105x^2+80=200x
The zeros of 105x^2+80=200x are x= 4/3 ,x= 4/7